You are given the customer visit log of a shop represented by a 0-indexed string customers consisting only of characters 'N' and 'Y':
ith character is 'Y', it means that customers come at the ith hour'N' indicates that no customers come at the ith hour.If the shop closes at the jth hour (0 <= j <= n), the penalty is calculated as follows:
1.1.Return the earliest hour at which the shop must be closed to incur a minimum penalty.
+ +Note that if a shop closes at the jth hour, it means the shop is closed at the hour j.
+
Example 1:
+ ++Input: customers = "YYNY" +Output: 2 +Explanation: +- Closing the shop at the 0th hour incurs in 1+1+0+1 = 3 penalty. +- Closing the shop at the 1st hour incurs in 0+1+0+1 = 2 penalty. +- Closing the shop at the 2nd hour incurs in 0+0+0+1 = 1 penalty. +- Closing the shop at the 3rd hour incurs in 0+0+1+1 = 2 penalty. +- Closing the shop at the 4th hour incurs in 0+0+1+0 = 1 penalty. +Closing the shop at 2nd or 4th hour gives a minimum penalty. Since 2 is earlier, the optimal closing time is 2. ++ +
Example 2:
+ ++Input: customers = "NNNNN" +Output: 0 +Explanation: It is best to close the shop at the 0th hour as no customers arrive.+ +
Example 3:
+ ++Input: customers = "YYYY" +Output: 4 +Explanation: It is best to close the shop at the 4th hour as customers arrive at each hour. ++ +
+
Constraints:
+ +1 <= customers.length <= 105customers consists only of characters 'Y' and 'N'.