From 10ff3a0da5837196ad0bd8118b04c90a7997dc0e Mon Sep 17 00:00:00 2001 From: Deven <63876261+devenperez@users.noreply.github.com> Date: Sun, 30 Nov 2025 22:34:12 -0500 Subject: [PATCH] Create README - LeetHub --- 2483-minimum-penalty-for-a-shop/README.md | 55 +++++++++++++++++++++++ 1 file changed, 55 insertions(+) create mode 100644 2483-minimum-penalty-for-a-shop/README.md diff --git a/2483-minimum-penalty-for-a-shop/README.md b/2483-minimum-penalty-for-a-shop/README.md new file mode 100644 index 0000000..73ad7f9 --- /dev/null +++ b/2483-minimum-penalty-for-a-shop/README.md @@ -0,0 +1,55 @@ +

2483. Minimum Penalty for a Shop

Medium

You are given the customer visit log of a shop represented by a 0-indexed string customers consisting only of characters 'N' and 'Y':

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If the shop closes at the jth hour (0 <= j <= n), the penalty is calculated as follows:

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Return the earliest hour at which the shop must be closed to incur a minimum penalty.

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Note that if a shop closes at the jth hour, it means the shop is closed at the hour j.

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Example 1:

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+Input: customers = "YYNY"
+Output: 2
+Explanation: 
+- Closing the shop at the 0th hour incurs in 1+1+0+1 = 3 penalty.
+- Closing the shop at the 1st hour incurs in 0+1+0+1 = 2 penalty.
+- Closing the shop at the 2nd hour incurs in 0+0+0+1 = 1 penalty.
+- Closing the shop at the 3rd hour incurs in 0+0+1+1 = 2 penalty.
+- Closing the shop at the 4th hour incurs in 0+0+1+0 = 1 penalty.
+Closing the shop at 2nd or 4th hour gives a minimum penalty. Since 2 is earlier, the optimal closing time is 2.
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Example 2:

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+Input: customers = "NNNNN"
+Output: 0
+Explanation: It is best to close the shop at the 0th hour as no customers arrive.
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Example 3:

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+Input: customers = "YYYY"
+Output: 4
+Explanation: It is best to close the shop at the 4th hour as customers arrive at each hour.
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+ +

 

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Constraints:

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