From 183d2978024c374f5c1a779c5b70ce98fedb6cfc Mon Sep 17 00:00:00 2001 From: Deven <63876261+devenperez@users.noreply.github.com> Date: Fri, 20 Jan 2023 19:24:53 -0500 Subject: [PATCH] Create README - LeetHub --- .../README.md | 44 +++++++++++++++++++ 1 file changed, 44 insertions(+) create mode 100644 181-employees-earning-more-than-their-managers/README.md diff --git a/181-employees-earning-more-than-their-managers/README.md b/181-employees-earning-more-than-their-managers/README.md new file mode 100644 index 0000000..7300703 --- /dev/null +++ b/181-employees-earning-more-than-their-managers/README.md @@ -0,0 +1,44 @@ +

181. Employees Earning More Than Their Managers

Easy


SQL Schema

Table: Employee

+ +
+-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| id          | int     |
+| name        | varchar |
+| salary      | int     |
+| managerId   | int     |
++-------------+---------+
+id is the primary key column for this table.
+Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.
+
+ +

 

+ +

Write an SQL query to find the employees who earn more than their managers.

+ +

Return the result table in any order.

+ +

The query result format is in the following example.

+ +

 

+

Example 1:

+ +
Input: 
+Employee table:
++----+-------+--------+-----------+
+| id | name  | salary | managerId |
++----+-------+--------+-----------+
+| 1  | Joe   | 70000  | 3         |
+| 2  | Henry | 80000  | 4         |
+| 3  | Sam   | 60000  | Null      |
+| 4  | Max   | 90000  | Null      |
++----+-------+--------+-----------+
+Output: 
++----------+
+| Employee |
++----------+
+| Joe      |
++----------+
+Explanation: Joe is the only employee who earns more than his manager.
+
+
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