From 183d2978024c374f5c1a779c5b70ce98fedb6cfc Mon Sep 17 00:00:00 2001 From: Deven <63876261+devenperez@users.noreply.github.com> Date: Fri, 20 Jan 2023 19:24:53 -0500 Subject: [PATCH] Create README - LeetHub --- .../README.md | 44 +++++++++++++++++++ 1 file changed, 44 insertions(+) create mode 100644 181-employees-earning-more-than-their-managers/README.md diff --git a/181-employees-earning-more-than-their-managers/README.md b/181-employees-earning-more-than-their-managers/README.md new file mode 100644 index 0000000..7300703 --- /dev/null +++ b/181-employees-earning-more-than-their-managers/README.md @@ -0,0 +1,44 @@ +
Table: Employee
+-------------+---------+ +| Column Name | Type | ++-------------+---------+ +| id | int | +| name | varchar | +| salary | int | +| managerId | int | ++-------------+---------+ +id is the primary key column for this table. +Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager. ++ +
+ +
Write an SQL query to find the employees who earn more than their managers.
+ +Return the result table in any order.
+ +The query result format is in the following example.
+ ++
Example 1:
+ +Input: +Employee table: ++----+-------+--------+-----------+ +| id | name | salary | managerId | ++----+-------+--------+-----------+ +| 1 | Joe | 70000 | 3 | +| 2 | Henry | 80000 | 4 | +| 3 | Sam | 60000 | Null | +| 4 | Max | 90000 | Null | ++----+-------+--------+-----------+ +Output: ++----------+ +| Employee | ++----------+ +| Joe | ++----------+ +Explanation: Joe is the only employee who earns more than his manager. ++