From 59813bed8338ba6834c491ae91c6cae968cb2225 Mon Sep 17 00:00:00 2001 From: devenperez <63876261+devenperez@users.noreply.github.com> Date: Mon, 11 Jul 2022 23:35:32 -0400 Subject: [PATCH] Removed "Two Sum" for testing purposes --- 1-two-sum/1-two-sum.js | 14 -------------- 1-two-sum/1-two-sum.py | 11 ----------- 1-two-sum/NOTES.md | 1 - 1-two-sum/README.md | 38 -------------------------------------- 4 files changed, 64 deletions(-) delete mode 100644 1-two-sum/1-two-sum.js delete mode 100644 1-two-sum/1-two-sum.py delete mode 100644 1-two-sum/NOTES.md delete mode 100644 1-two-sum/README.md diff --git a/1-two-sum/1-two-sum.js b/1-two-sum/1-two-sum.js deleted file mode 100644 index 56e2ac7..0000000 --- a/1-two-sum/1-two-sum.js +++ /dev/null @@ -1,14 +0,0 @@ -/** - * @param {number[]} nums - * @param {number} target - * @return {number[]} - */ -var twoSum = function(nums, target) { - for(let i = 0; i < nums.length; i++) { - for(let j = i + 1; j < nums.length; j++) { - if(nums[i] + nums[j] == target) { - return [i, j]; - } - } - } -}; \ No newline at end of file diff --git a/1-two-sum/1-two-sum.py b/1-two-sum/1-two-sum.py deleted file mode 100644 index 3e543b6..0000000 --- a/1-two-sum/1-two-sum.py +++ /dev/null @@ -1,11 +0,0 @@ -class Solution(object): - def twoSum(self, nums, target): - """ - :type nums: List[int] - :type target: int - :rtype: List[int] - """ - for i in range(len(nums)): - for j in range(i + 1, len(nums)): - if nums[i] + nums[j] == target: - return [i, j] \ No newline at end of file diff --git a/1-two-sum/NOTES.md b/1-two-sum/NOTES.md deleted file mode 100644 index 38c1374..0000000 --- a/1-two-sum/NOTES.md +++ /dev/null @@ -1 +0,0 @@ -​ \ No newline at end of file diff --git a/1-two-sum/README.md b/1-two-sum/README.md deleted file mode 100644 index 2776ef3..0000000 --- a/1-two-sum/README.md +++ /dev/null @@ -1,38 +0,0 @@ -

1. Two Sum

Easy


Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

- -

You may assume that each input would have exactly one solution, and you may not use the same element twice.

- -

You can return the answer in any order.

- -

 

-

Example 1:

- -
Input: nums = [2,7,11,15], target = 9
-Output: [0,1]
-Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
-
- -

Example 2:

- -
Input: nums = [3,2,4], target = 6
-Output: [1,2]
-
- -

Example 3:

- -
Input: nums = [3,3], target = 6
-Output: [0,1]
-
- -

 

-

Constraints:

- - - -

 

-Follow-up: Can you come up with an algorithm that is less than O(n2time complexity?
\ No newline at end of file