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 <h2><a href="https://leetcode.com/problems/two-sum/">1. Two Sum</a></h2><h3>Easy</h3><hr><div><p>Given an array of integers <code>nums</code>&nbsp;and an integer <code>target</code>, return <em>indices of the two numbers such that they add up to <code>target</code></em>.</p>
 <p>You may assume that each input would have <strong><em>exactly</em> one solution</strong>, and you may not use the <em>same</em> element twice.</p>
 <p>You can return the answer in any order.</p>
 <p>&nbsp;</p>
 <p><strong>Example 1:</strong></p>
 <pre><strong>Input:</strong> nums = [2,7,11,15], target = 9
 <strong>Output:</strong> [0,1]
 <strong>Explanation:</strong> Because nums[0] + nums[1] == 9, we return [0, 1].
 </pre>
 <p><strong>Example 2:</strong></p>
 <pre><strong>Input:</strong> nums = [3,2,4], target = 6
 <strong>Output:</strong> [1,2]
 </pre>
 <p><strong>Example 3:</strong></p>
 <pre><strong>Input:</strong> nums = [3,3], target = 6
 <strong>Output:</strong> [0,1]
 </pre>
 <p>&nbsp;</p>
 <p><strong>Constraints:</strong></p>
 <ul>
 	<li><code>2 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>
 	<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
 	<li><code>-10<sup>9</sup> &lt;= target &lt;= 10<sup>9</sup></code></li>
 	<li><strong>Only one valid answer exists.</strong></li>
 </ul>
 <p>&nbsp;</p>
 <strong>Follow-up:&nbsp;</strong>Can you come up with an algorithm that is less than&nbsp;<code>O(n<sup>2</sup>)&nbsp;</code>time complexity?</div>