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+<h2><a href="https://leetcode.com/problems/sleep">2621. Sleep</a></h2><h3>Easy</h3><hr><p>Given&nbsp;a positive integer <code>millis</code>, write an asynchronous function that sleeps for <code>millis</code>&nbsp;milliseconds. It can resolve any value.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> millis = 100
+<strong>Output:</strong> 100
+<strong>Explanation:</strong> It should return a promise that resolves after 100ms.
+let t = Date.now();
+sleep(100).then(() =&gt; {
+  console.log(Date.now() - t); // 100
+});
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> millis = 200
+<strong>Output:</strong> 200
+<strong>Explanation:</strong> It should return a promise that resolves after 200ms.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= millis &lt;= 1000</code></li>
+</ul>