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Time: 3 ms (73%), Space: 17.8 MB (84.61%) - LeetHub
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution:
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def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]:
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"""
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Complexities:
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Time: O(n)
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Space: O(1)
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where n = max(len(l1), len(l2))
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"""
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# Addition by place value
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currNode1 = l1
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currNode2 = l2
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sumNode = None
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tailNode = None
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carry = 0
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placeValue = 1
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# Loop through nodes until reached end of both lists
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while currNode1 or currNode2:
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v1 = currNode1.val if currNode1 else 0
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v2 = currNode2.val if currNode2 else 0
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sumVal = (v1 + v2 + carry) * placeValue
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val = sumVal % 10
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carry = sumVal // 10
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newNode = ListNode(val)
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if sumNode == None:
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sumNode = newNode
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else:
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tailNode.next = newNode
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tailNode = newNode
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currNode1 = currNode1.next if currNode1 else None
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currNode2 = currNode2.next if currNode2 else None
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if carry:
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tailNode.next = ListNode(carry)
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return sumNode or ListNode(0)
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