From 947f4f775ac4371c92972000e2ef04ee791a21a3 Mon Sep 17 00:00:00 2001 From: Deven <63876261+devenperez@users.noreply.github.com> Date: Tue, 7 Feb 2023 14:52:15 -0500 Subject: [PATCH] Create README - LeetHub --- 231-power-of-two/README.md | 34 ++++++++++++++++++++++++++++++++++ 1 file changed, 34 insertions(+) create mode 100644 231-power-of-two/README.md diff --git a/231-power-of-two/README.md b/231-power-of-two/README.md new file mode 100644 index 0000000..b6b0cad --- /dev/null +++ b/231-power-of-two/README.md @@ -0,0 +1,34 @@ +

231. Power of Two

Easy


Given an integer n, return true if it is a power of two. Otherwise, return false.

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An integer n is a power of two, if there exists an integer x such that n == 2x.

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Example 1:

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Input: n = 1
+Output: true
+Explanation: 20 = 1
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Example 2:

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Input: n = 16
+Output: true
+Explanation: 24 = 16
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Example 3:

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Input: n = 3
+Output: false
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Constraints:

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+Follow up: Could you solve it without loops/recursion?
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