Table: Employees
+-------------+---------+ +| Column Name | Type | ++-------------+---------+ +| employee_id | int | +| name | varchar | +| salary | int | ++-------------+---------+ +employee_id is the primary key for this table. +Each row of this table indicates the employee ID, employee name, and salary. ++ +
+ +
Write an SQL query to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee name does not start with the character 'M'. The bonus of an employee is 0 otherwise.
Return the result table ordered by employee_id.
The query result format is in the following example.
+ ++
Example 1:
+ +Input: +Employees table: ++-------------+---------+--------+ +| employee_id | name | salary | ++-------------+---------+--------+ +| 2 | Meir | 3000 | +| 3 | Michael | 3800 | +| 7 | Addilyn | 7400 | +| 8 | Juan | 6100 | +| 9 | Kannon | 7700 | ++-------------+---------+--------+ +Output: ++-------------+-------+ +| employee_id | bonus | ++-------------+-------+ +| 2 | 0 | +| 3 | 0 | +| 7 | 7400 | +| 8 | 0 | +| 9 | 7700 | ++-------------+-------+ +Explanation: +The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id. +The employee with ID 3 gets 0 bonus because their name starts with 'M'. +The rest of the employees get a 100% bonus. ++