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+<h2><a href="https://leetcode.com/problems/sqrtx/">69. Sqrt(x)</a></h2><h3>Easy</h3><hr><div><p>Given a non-negative integer <code>x</code>, return <em>the square root of </em><code>x</code><em> rounded down to the nearest integer</em>. The returned integer should be <strong>non-negative</strong> as well.</p>
+
+<p>You <strong>must not use</strong> any built-in exponent function or operator.</p>
+
+<ul>
+	<li>For example, do not use <code>pow(x, 0.5)</code> in c++ or <code>x ** 0.5</code> in python.</li>
+</ul>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre><strong>Input:</strong> x = 4
+<strong>Output:</strong> 2
+<strong>Explanation:</strong> The square root of 4 is 2, so we return 2.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre><strong>Input:</strong> x = 8
+<strong>Output:</strong> 2
+<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>0 &lt;= x &lt;= 2<sup>31</sup> - 1</code></li>
+</ul>
+</div>
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