mirror of
https://github.com/devenperez/leetcode.git
synced 2026-06-13 14:57:08 +00:00
Deven
28 lines
802 B
Python
28 lines
802 B
Python
class Solution:
|
|
def numIdenticalPairs(self, nums: List[int]) -> int:
|
|
count = 0
|
|
|
|
while len(nums) > 0:
|
|
oldLength = len(nums)
|
|
|
|
# Removes all instances of nums[0]
|
|
nums = [ n for n in nums if n != nums[0] ]
|
|
|
|
numOccurances = oldLength - len(nums)
|
|
|
|
if numOccurances > 1:
|
|
count += int((numOccurances * (numOccurances - 1)) / 2) # numOccurances choose 2
|
|
|
|
return count
|
|
|
|
"""
|
|
## Straight-forward solution
|
|
count = 0
|
|
|
|
for i in range(len(nums)):
|
|
for j in range(i + 1, len(nums)):
|
|
if nums[i] == nums[j]:
|
|
count += 1
|
|
|
|
return count
|
|
""" |