Files
leetcode/0238-product-of-array-except-self/0238-product-of-array-except-self.py
T

15 lines
446 B
Python

class Solution:
def productExceptSelf(self, nums: List[int]) -> List[int]:
n = len(nums)
left = [1] * len(nums)
right = [1] * len(nums)
for i in range(len(nums)):
if i > 0:
left[i] = left[i - 1] * nums[i - 1]
if n - i < len(nums):
right[n - i - 1] = right[n - i] * nums[n - i]
return [left[i] * right[i] for i in range(len(nums))]