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Deven
18 lines
488 B
Python
18 lines
488 B
Python
import heapq
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class Solution:
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def findKthLargest(self, nums: List[int], k: int) -> int:
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heap = nums[:k]
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# Heapify (min) the first k elements
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heapq.heapify(heap)
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# iterate over k+1...n - O(n) times
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# - if larger than min in heap, replace min - O(log k)
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# - else do nothing
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for num in nums:
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if num > heap[0]:
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heapq.heapreplace(heap, num)
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# return min in heap
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return heap[0] |