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leetcode/0213-house-robber-ii/0213-house-robber-ii.py
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Python

class Solution:
def rob(self, nums: List[int]) -> int:
n = len(nums) - 1
dp = [0] * n # Best of first i houses
dp2 = [0] * n # Best of first i houses without robbing the first one
if len(nums) == 1:
return nums[0]
elif len(nums) == 2:
return max(nums[0], nums[1])
if n >= 1:
dp[0] = nums[0]
dp2[0] = 0
if n >= 2:
dp[1] = max(nums[0], nums[1])
dp2[1] = nums[1]
if n >= 3:
dp[2] = max(nums[0] + nums[2], nums[1])
dp2[2] = max(nums[1], nums[2])
if n >= 4:
dp[3] = max(nums[3] + dp2[1], nums[2] + dp2[0])
dp2[3] = max(nums[1] + nums[3], nums[2])
for i in range(3, n):
dp[i] = max(nums[i] + dp[i - 2], nums[i - 1] + dp[i - 3])
dp2[i] = max(nums[i] + dp2[i - 2], nums[i - 1] + dp2[i - 3])
return max(dp[-1], dp2[-2] + nums[-1])