Time: 0 ms (100%), Space: 18.8 MB (17.56%) - LeetHub

This commit is contained in:
Deven
2025-10-02 12:51:44 -04:00
parent 5b455306a4
commit 3a118eb0b4
@@ -0,0 +1,35 @@
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
if root is None:
return []
outNodes = [[root]]
out = [[root.val]]
nextHasChildren = root.left is not None or root.right is not None
while nextHasChildren:
nextHasChildren = False
nextLevel = []
nextLevelNodes = []
for node in outNodes[-1]:
if node.left is not None:
nextLevel.append(node.left.val)
nextLevelNodes.append(node.left)
nextHasChildren |= node.left.left is not None or node.left.right is not None
if node.right is not None:
nextLevel.append(node.right.val)
nextLevelNodes.append(node.right)
nextHasChildren |= node.right.left is not None or node.right.right is not None
out.append(nextLevel)
outNodes.append(nextLevelNodes)
return out