Time: 296 ms (15.20%), Space: 18.3 MB (22.11%) - LeetHub

1684-count-the-number-of-consistent-strings/1684-count-the-number-of-consistent-strings.py

@@ -0,0 +1,19 @@
+class Solution:
+    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
+        allowedFilter = [False] * 26
+        for c in allowed:
+            allowedFilter[ord(c) - ord('a')] = True
+        
+        numAllowedWords = 0
+        for i in range(len(words)):
+            allowedWord = True
+            for a in words[i]:
+                if not allowedFilter[ord(a) - ord('a')]:
+                    allowedWord = False
+                    break
+                
+            if allowedWord:
+                numAllowedWords += 1
+            
+        
+        return numAllowedWords