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3076-shortest-uncommon-substring-in-an-array/3076-shortest-uncommon-substring-in-an-array.py

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+class Solution:
+    def shortestSubstrings(self, arr: List[str]) -> List[str]:
+        max_len = max([len(x) for x in arr])
+        sol = [""] * len(arr)
+        for l in range(1, max_len + 1):
+            seen = {}
+            for i, x in enumerate(arr):
+                for j in range(len(x) - l + 1):
+                    window = x[j:j + l]
+                    if seen.get(window) == None or seen.get(window) == i:
+                        seen[window] = i
+                    else:
+                        seen[window] = -1
+
+            # Check if we found everything
+            for k in seen.keys():
+                if seen[k] == -1:
+                    continue
+                cur_sol = sol[seen[k]]
+                if len(cur_sol) == 0 or (len(k) <= len(cur_sol) and k < cur_sol):
+                    sol[seen[k]] = k
+
+            for i in range(len(arr)):
+                if len(sol[i]) == 0 and len(arr[i]) > l:
+                    break
+                if i == len(arr) - 1:
+                    return sol
+
+        return sol