Time: 1102 ms (11.58%), Space: 0B (100.00%) - LeetHub

This commit is contained in:
Deven
2023-01-20 20:50:09 -05:00
parent a4cbdc63aa
commit c48da342a3
@@ -0,0 +1,7 @@
# Write your MySQL query statement below
SELECT
cus.name as Customers
FROM Customers as cus
LEFT JOIN Orders ON cus.id = Orders.customerId
GROUP BY cus.id
HAVING count(Orders.customerId) = 0;