Time: 1102 ms (11.58%), Space: 0B (100.00%) - LeetHub

2026-06-15 09:57:09 +00:00 · 2023-01-20 20:50:09 -05:00
parent a4cbdc63aa
commit c48da342a3
1 changed files with 7 additions and 0 deletions
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 # Write your MySQL query statement below
 SELECT 
    cus.name as Customers
 FROM Customers as cus
    LEFT JOIN Orders ON cus.id = Orders.customerId
 GROUP BY cus.id
 HAVING count(Orders.customerId) = 0;