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+<h2><a href="https://leetcode.com/problems/rising-temperature/">197. Rising Temperature</a></h2><h3>Easy</h3><hr><div class="sql-schema-wrapper__3VBi"><a class="sql-schema-link__3cEg">SQL Schema<svg viewBox="0 0 24 24" width="1em" height="1em" class="icon__1Md2"><path fill-rule="evenodd" d="M10 6L8.59 7.41 13.17 12l-4.58 4.59L10 18l6-6z"></path></svg></a></div><div><p>Table: <code>Weather</code></p>
+
+<pre>+---------------+---------+
+| Column Name   | Type    |
+---------------+---------+
+| id            | int     |
+| recordDate    | date    |
+| temperature   | int     |
+---------------+---------+
+id is the primary key for this table.
+This table contains information about the temperature on a certain day.
+</pre>
+
+<p>&nbsp;</p>
+
+<p>Write an SQL query to find all dates' <code>Id</code> with higher temperatures compared to its previous dates (yesterday).</p>
+
+<p>Return the result table in <strong>any order</strong>.</p>
+
+<p>The query result format is in the following example.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre><strong>Input:</strong> 
+Weather table:
+----+------------+-------------+
+| id | recordDate | temperature |
+----+------------+-------------+
+| 1  | 2015-01-01 | 10          |
+| 2  | 2015-01-02 | 25          |
+| 3  | 2015-01-03 | 20          |
+| 4  | 2015-01-04 | 30          |
+----+------------+-------------+
+<strong>Output:</strong> 
+----+
+| id |
+----+
+| 2  |
+| 4  |
+----+
+<strong>Explanation:</strong> 
+In 2015-01-02, the temperature was higher than the previous day (10 -&gt; 25).
+In 2015-01-04, the temperature was higher than the previous day (20 -&gt; 30).
+</pre>
+</div>